Well, when a parabola is in the form y=ax^2+bx+c, we know that c is the y-intercept.
So all we need to do with this equation is expand it into that form.
y = (x-1)(x+3)
Expand
y = x^2-1x+3x-3
Collect like terms
y = x^2+2x-3
And there you have it. Your y-intercept is -3.
It is an up parabola.
x-intercept = -21y-intercept = 168
It is the parabola such that the coordinates of each point on it satisfies the given equation.
It is a quadratic function which represents a parabola.
slope = -1y-intercept = 5
It is an up parabola.
It is the equation of a parabola.
The intercept is [ y = 7 ] .
The y intercept is 1
x-intercept = -21y-intercept = 168
It is the parabola such that the coordinates of each point on it satisfies the given equation.
No, that's a parabola.
7 is the y intercept
It is a quadratic function which represents a parabola.
y intercept 7 x intercept 7/3
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
The y intercept is at co-ordinates (0,b).