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When the vertex lies on the x-axis.

For example x = y2, the vertex is at the origin, and the parabola is lying on its side.

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Q: How do you get a parabola with only one x intercept?
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Does a parabola have to have an x-intercept?

No, a parabola does not have to have an x-intercept. ex. -2(x-2)^2 - 4 is a parabola that has no x-intercept.


Does a parabola always have 2 x intercepts?

No, if the vertex of the parabola is (0, 0) it will only have one x intercept. The parabola might have zero x intercepts as well. For example: Y= x^2 + 1 would never touch the x line.


What is the vertex of a parabola?

the vertex of a parabola is the 2 x-intercepts times-ed and then divided by two (if there is only 1 x-intercept then that is the vertex)


What is the parabola?

A parabola is a type of graph that is not linear, and mostly curved. A parabola has the "x squared" sign in it's equation. A parabola is not only curved, but all the symmetrical. The symmetrical point, the middle of the parabola is called the vertex. You can graph this graph with the vertex, x-intercepts and a y-intercept. A parabola that has a positive x squared would be a smile parabola, and the one with the negative x squared would be a frown parabola. Also, there are the parabolas that are not up or down, but sideways Those parabolas have x=y squared, instead of y = x squared.


Find the x intercept or interceptss and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?

-2, 6


How do you find the y intercept when given a parabola in standard form?

At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".


When would not having a parabola x- intercept happen?

Consider a parabola described by the expression y = ax2 + bx + c first, calculate it's first and second derivatives: y' = 2ax + b y'' = 2a Find x value at which y' = 0, and calculate whether the corresponding y-coordinate is above or below the x-axis. If it's above the x-axis, then the parabola will not intercept the x-axis if y'' is greater than 0. If it's below the x-axis, then the parabola will not intercept the x-axis if y'' is less than 0. Otherwise, it will always intercept the x axis at two locations.


How do you find the y intercept on a parabola?

If you know the equation, you just plug in x = 0 and solve.


Can a function only have one x - intercept and one y - intercept?

Yes. A straight line for example, such as y = x.


What is the definition of graph intercept?

The intercept of a graph is the point where is crosses one of the coordinate axes. The x intercept is where it crosses the x axis, the y intercept where it crosses the y axis. If the graph is given as y equals a function of x, it is usually easier to find the y intercept, because that is where x is 0. You just plug in 0 for x and evaluate. To find the x intercept, you plug in 0 for y and then you have to solve an equation for x. This is fairly easy if it is a linear equation (the graph is a straight line), somewhat harder for a quadratic (a parabola). But anyway you only asked for a definition, and I have given it.


How do you find y and x intercept of parabola?

For the equation of any graph. The graph intercepts the y-axis, when x is zero, so in the equation, substitute x=0, and solve for y. To find the x-intercept, this is when y is zero, so substitute y=0, and solve for x. For a parabola, if the highest power of y is the 1st power (no exponent) and the highest power of x is 2, then the parabola opens up or down. The parabola will have 1 y-intercept (usually it is the constant value), and depending on where it is (if it is at the origin, it is also an x-intercept, and the other x-intercept has the same distance as y-intercept has from the axis of symmetry i.e y = a2x + bx), either have 2 x-intercepts, or no interceptions with the x-axis (i.e. y = x2 + c, c ≥ 0 or y = -x2 + c, c ≤ 0). If the highest power of y is 2, and highest power of x is 1, then it opens left or right, and it may have none or 2 y-intercepts, and will have 1 x-intercept. So when you're solving for the one that's a quadratic, if you come up with imaginary or complex roots, that means there is no intercept.


Find the x intercept or intercepts and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?

The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.