it is 1
IN his head, bitchez! Or in longer words: by noting 1+100=101, 2+99=101, ... , 50+51=101 50 pairs of numbers summing to 101, so 50x101 = 5050
Gauss's method was to find the sum of 1-100. He tried adding with pairs 1 + 100 = 101, 2 + 99 = 101 and so on. Each pairs was going to equal 101. Half of 100 is 50, 50 x 101 = 5,050.
The only numbers that divide evenly into 101 are 101 and 1. This means that 101 is a prime number.
A centillion = 10303 So sqrt(centillion) = (10303)1/2 = 101/2*(10302)1/2 = sqrt(10)*10151 = 3.162*10151 approx.
closer to 1.2
Closer to 1/2
It is closer to 1/2
2/5 is closer to 0.
0
0.67 is closer to 1
101 X 1 = 101
it's closer to 1/2 1/2 = 3/6 2/3 = 4/6 1 = 6/6 4 is closer to 3 so 2/3 is closer to 1/2
2/5 is closer.
It's............101-102=1......right?.........well..........101-102+1.....with an expoent of 2 in 10"2"!
No. .2 is closer to .6
The sum of numbers from 1 to 101 can be calculated using the formula for the sum of an arithmetic series, which is n/2 * (first term + last term), where n is the number of terms. In this case, the first term is 1, the last term is 101, and there are 101 terms in total. Plugging these values into the formula, we get 101/2 * (1 + 101) = 101/2 * 102 = 5151. Therefore, the sum of numbers from 1 to 101 is 5151.
obviously closer to 1