no. this is a displacement
5 metres per second squared
If Ted swam 25 m east in a lake and turned and swam 75 m east he swam 100 m total. The displacement of 50 m only takes into account his starting and ending positions, not the travel route.
5(m-2) - m(m-2)
-2 m/s^2
9.81 m/s2
5 m/s2 east
Acceleration = rate of change of speed = (change of speed) / (time interval) = (25 - 5) / 4 = 20/4 = 5 m/s2
Use the expression a = F/m Given F = 10 N and m = 5 kg. So acceleration a = 10/5 = 2 m/s2
If you drop the rock at the Earth's surface the acceleration is the same for both distances, 32 Feet/second2, the acceleration due to gravity.
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
north-south east-west =5 east and 15 north
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
The resulting acceleration is 2 meters per second squared. Acceleration = F/m
Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.
east of 5
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
Force = mass × acceleration = 5 kg × 3 m/s² = 15 N