If the distribution is positively skewed , then the mean will always be the highest estimate of central tendency and the mode will always be the lowest estimate of central tendency (If it is a uni-modal distribution). If the distribution is negatively skewed then mean will always be the lowest estimate of central tendency and the mode will be the highest estimate of central tendency.
In both positive and negative skewed distribution the median will always be between the mean and the mode. If a distribution is less symmetrical and more skewed, you are better of using the median over the mean.
Yes, it is.
The mean is the average: (2+15+21+27+31+42+55) divided by the number of terms (7). The mean is 193/7 = 27.6 The median is the number from the set which is in the middle, when listed lowest to highest, which you have already done. With your odd numbered set of 7 values, three numbers will be below the median, and three numbers above. The median is 27. If you had an even-numbered set, the median would be half-way between the two middle values of the set. In your example, there is no mode. The mode in a set of data is the value that occurs most often. No element in your set occurs more than once, and so there is no mode.
A mode of 12 means 12 happens more often than any other. Put two twelves in the set and one of the other numbers. A median of 9 means that 9 is the middle number of the set. You already have two twelves, so you're looking for two single numbers less than 9. A mean of 9 means that the entire set totals 45. You already have 33. (5, 7, 9, 12, 12) is one set with those specifications. There are many others.
The mean is the average (all numbers added and divided by the number of values) The median is the middle number when arranged numerically low-to-high The mode is the most frequently appearing number. 92 86 90 74 95 100 90 50 arrange them for more readability: 50, 74, 86, 90, 90, 92, 95, 100 For the mean: 50+74+86+90+90+92+95+100 = 677 There are 8 numbers, so 677/8, 677/8 = 84.625 or 84 5/8 For the median: Since there are an even number of values, you add the two center values, and divide by two. 90 + 90 = 180 180 / 2 = 90 For the mode: The number 90 appears twice, which is the most frequent, so the mode is 90.
An outlier can be very large or small. its usally 1.5 times the mean. they can be seen with a cat and whisker box * * * * * The answer to the question is YES. "Its usually 1.5 times the mean" is utter rubbish - apart from the typo. If a distribution had a mean of zero, such as the standard Normal distribution, then almost every observation would be greater than 1.5 times the mean = 0 and so almost every observation would be an outlier! No. There is no universally agreed definition for an outlier but one contender is values that are more than 1.5 times the interquartile range away from the median.
A measure of skewness is Pearson's Coefficient of Skew. It is defined as: Pearson's Coefficient = 3(mean - median)/ standard deviation The coefficient is positive when the median is less than the mean and in that case the tail of the distribution is skewed to the right (notionally the positive section of a cartesian frame). When the median is more than the mean, the cofficient is negative and the tail of the distribution is skewed in the left direction i.e. it is longer on the left side than on the right.
The skewness of a random variable X is the third standardised moment of the distribution. If the mean of the distribution is m and the standard deviation is s, then the skewness, g1 = E[{(X - m)/s}3] where E is the expected value. Skewness is a measure of the degree to which data tend to be on one side of the mean or the other. A skewness of zero indicates symmetry. Positive skewness indicates there are more values that are below the mean but the the ones that are above the mean, although fewer, are substantially bigger. Negative skewness is defined analogously.
A positive skewness is when the value of mean is greater than the mode. that is, the curve is more skewed at the right hand side or the right tail is longer than the left tail. The negative skewness is when the mean is smaller than the mode, and in this case the curve is more skewed on the left hand side.
Skewness is a measure of the extent to which the probability distribution of a random variable lies more to one side of the mean, as opposed to it being exactly symmetrical.If μ and s are the mean and standard deviation of a random variable X, thenSkew(X) = Expected value of [(X - μ)/s]3
When the distribution has outliers. They will skew the mean but will not affect the median.
Both the mean and median represent the center of a distribution. Calculating the mean is easier, but may be more affected by outliers or extreme values. The median is more robust.
in general,mean is more stable than median but in the case of extreme values it is better to consider median a stable measure than mean.
Yes
Technically the mean is more accurate, but it is not always a true representation, when you have a number that is way out of proportion with the rest of the numbers. That is when the median is more useful. See the related question below.
In maths, the median is connected with the mode, mean. Help learn theese by singing a song, more of a chant though. Mode most Median middle Mean add up and divide Mode most Median middle Mean add up and divide!!
The mean is 1226.75. The median is 508. There is no mode as no number occurs more than any other.
cos mean is the average and median is putting them in ascending order and selecting the middle one example: 23 ,24 ,27 ,28 ,29 mean= 26.2(it's like it's in the middle) Median= 27 now, which do you think is more accurate??:)