If the distribution is positively skewed , then the mean will always be the highest estimate of central tendency and the mode will always be the lowest estimate of central tendency (If it is a uni-modal distribution). If the distribution is negatively skewed then mean will always be the lowest estimate of central tendency and the mode will be the highest estimate of central tendency.
In both positive and negative skewed distribution the median will always be between the mean and the mode. If a distribution is less symmetrical and more skewed, you are better of using the median over the mean.
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Yes, it is.
The mean is the average: (2+15+21+27+31+42+55) divided by the number of terms (7). The mean is 193/7 = 27.6 The median is the number from the set which is in the middle, when listed lowest to highest, which you have already done. With your odd numbered set of 7 values, three numbers will be below the median, and three numbers above. The median is 27. If you had an even-numbered set, the median would be half-way between the two middle values of the set. In your example, there is no mode. The mode in a set of data is the value that occurs most often. No element in your set occurs more than once, and so there is no mode.
A mode of 12 means 12 happens more often than any other. Put two twelves in the set and one of the other numbers. A median of 9 means that 9 is the middle number of the set. You already have two twelves, so you're looking for two single numbers less than 9. A mean of 9 means that the entire set totals 45. You already have 33. (5, 7, 9, 12, 12) is one set with those specifications. There are many others.
The mean is the average (all numbers added and divided by the number of values) The median is the middle number when arranged numerically low-to-high The mode is the most frequently appearing number. 92 86 90 74 95 100 90 50 arrange them for more readability: 50, 74, 86, 90, 90, 92, 95, 100 For the mean: 50+74+86+90+90+92+95+100 = 677 There are 8 numbers, so 677/8, 677/8 = 84.625 or 84 5/8 For the median: Since there are an even number of values, you add the two center values, and divide by two. 90 + 90 = 180 180 / 2 = 90 For the mode: The number 90 appears twice, which is the most frequent, so the mode is 90.
An outlier can be very large or small. its usally 1.5 times the mean. they can be seen with a cat and whisker box * * * * * The answer to the question is YES. "Its usually 1.5 times the mean" is utter rubbish - apart from the typo. If a distribution had a mean of zero, such as the standard Normal distribution, then almost every observation would be greater than 1.5 times the mean = 0 and so almost every observation would be an outlier! No. There is no universally agreed definition for an outlier but one contender is values that are more than 1.5 times the interquartile range away from the median.