No Actually... x^(-y) is equal to 1/x^y. 2^(-2) is equal to 1/2^2 which is equal to 1/4 or 0.25.
135
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
It equels 10* * * * *The answer depends on the values of x and y.
If x+y = 3 and y times x = 2 then y = 1.
This is definitely false; if x=2 and y=3, x to the y power is 8, but y to the x power is 9, which are not equal.
By definition of powers, x to the power y = x*x*x*........y times x to the power 1 = x Therefore, 10 to the power 1 = 10.
That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy
No
what is a program x and y
Let [x percent of y] = (x/100)*y. And [y percent of x] = (y/100)*x.Use the ruSo the first one (x/100)*y = y*(x /100) = y*x/100.The second one: (y/100)*x = x*(y/100) = x * y / 100, which equals y*x/100.So yes they equal the same thing, so they are equal.
y = x + ex then dy/dx = 1 + ex and d2y/dx2 = ex
x2 is an expression that can be read "x squared" or "x to the power of two". It is equal to x times x.
Assuming y' is dy/dx, y = x^4/4 + yx^2
x^y.
x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
x < y : x is less than y.x ≤ y : x is less than or equal to y. x > y : x is greater than y.x ≥ y : x is greater than or equal to y.