Q: Is the cube root of negative number a positive?

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The cube root of a negative number is negative.

If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">

Any real number - positive or negative - has exactly one real cube root. Any real number (except zero) has three cubic roots in the complex numbers; but only one of them is real.

For the same reason that the square root of ANY negative number is not a real number.Real numbers are positive, negative, or zero. * The square of a positive number is a positive number. * The square of a negative number is a positive number. * The square of zero is zero. In other words, in no case will you get a REAL number whose square is a negative number. The square roots of negative numbers are said to be "imaginary" - a name given for historical reasons. They are just as "real" or "unreal" as the so-called real numbers, but the point is that they are a different kind of numbers.

The cube root of the number 8 is 2(two). Cube Root-a number when multiplied 3 times equals a given number.

Related questions

The cube root of a negative number is negative

The cube root of a negative number is negative.

No.

You cannot get real square root of a negative number because two numbers multiplied by themselves are always positive You can always get a real cube root of a negative number because three negative numbers multiplied by themselves give a negative .

When two negative or two positive numbers are multiplied together, they always result in a positive number; and when a positive and a negative number are multiplied together, they will always result in a negative number. Thus, you cannot square root a negative number because there are no real numbers that, when squared, would result in a negative number. For example: (-2)(-2) = 4 (2)(2) = 4 √4 = +/- 2 √(-4) = ? No real number, when squared, is a negative! Does not exist! The cube of a number is different, because you are multiplying three numbers together instead of just two. As a result, you can get a negative or a positive number. For example: (-2)(-2)(-2) = -8r (2)(2)(2) = 8 3√8 = 2 3√(-8) = -2

No, the cube root of -9 is an irrational number.

Because if you multiply a negative number three times, the product will be negative.

Every positive integer has two square roots, a positive square root and a negative square root. This is because, just like a positive number multiplied by a positive number is equal to a positive number, a negative number multiplied by a negative number is equal to a positive number. Therefore, rounded to two decimal places, the positive square root is equal to 7.28, and the negative square root is -7.28.

yes, you can find a real root to the cube root of any negative real number. There will also be two complex roots which satisfy it, as well.

I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..

It is always plus

If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">