For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6?
Check (0, 6):
y - 2x = 6, substitute 0 for x, and 6 for y into the equation
6 - 2(0) =? 6
6 - 0 =? 6
6 = 6 True, then (0, 6) is a solution.
Check (3, 1):
y - 2x = 6, substitute 3 for x, and 1 for y into the equation
1 - 2(3) =? 6
1 - 6 =? 6
-5 = 6 False, then (3, 1) is not a solution.
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∙ 11y agox = 12 y = 2 (12,2) satifies the equation
(10, 2)
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.
The ordered pair is (1, 3).
Will try elimination here.2X - 7Y = 0- 2(X - 6Y = - 5)2X - 7Y = 0- 2X + 12Y = 10------------------------------add5Y = 10Y = 2---------- find X ( second equation will do )X - 6(2) = - 5X - 12 = - 5X = 7-------------check both equations for consistancy2(7) - 7(2) = 014 - 14 = 00 = 0----------------first equation checks7 - 6(2) = - 57 - 12 = - 5- 5 = - 5---------------------------both check and are consistent(7, 2)------------------ordered pair
2x - 5y8 is an expression. It is not an equation and so cannot have a solution.
2x - 2y8 is an expression. It is not an equation and so cannot have a solution.
The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.
x = 12 y = 2 (12,2) satifies the equation
There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)
5x27
There are an infinite number of ordered pairs. (-5, -7) is one pair
-2,4
Yes. Yes, it could. So could (0, -1) or (2, 3). Or, if you want, (x, 2x-1).
There are several solutions....what are the choices you have? Guessing one of them is (1,-4) or possibly (-1,-5). --Algebra 2 Teacher
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
(-4,-5)