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For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6?

Check (0, 6):

y - 2x = 6, substitute 0 for x, and 6 for y into the equation

6 - 2(0) =? 6

6 - 0 =? 6

6 = 6 True, then (0, 6) is a solution.

Check (3, 1):

y - 2x = 6, substitute 3 for x, and 1 for y into the equation

1 - 2(3) =? 6

1 - 6 =? 6

-5 = 6 False, then (3, 1) is not a solution.

Q: Which ordered pair is a solution to the equation y - 2x 6?

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x = 12 y = 2 (12,2) satifies the equation

(10, 2)

Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation.

The ordered pair is (1, 3).

If an ordered pair is a solution to a system of linear equations, then algebraically it returns the same values when substituted appropriately into the x and y variables in each equation. For a very basic example: (0,0) satisfies the linear system of equations given by y=x and y=-2x By substituting in x=0 into both equations, the following is obtained: y=(0) and y=-2(0)=0 x=0 returns y=0 for both equations, which satisfies the ordered pair (0,0). This means that if an ordered pair is a solution to a system of equations, the x of that ordered pair returns the same y for all equations in the system. Graphically, this means that all equations in the system intersect at that point. This makes sense because an x value returns the same y value at that ordered pair, meaning all equations would have the same value at the x-coordinate of the ordered pair. The ordered pair specifies an intersection point of the equations.

Related questions

2x - 5y8 is an expression. It is not an equation and so cannot have a solution.

2x - 2y8 is an expression. It is not an equation and so cannot have a solution.

The equation 2x-5y=-1 has a graph that is a line. Every point on that line is an ordered pair that is a solution to the equation. So pick any real number x and plug it in. You will find a y and that pair (x,y) is an ordered pair that is a solution to this equation. For example, let x=0 Then we have -5y=-1so y=1/5 The ordered pair (0, 1/5) is a point on the line and a solution to the equation.

x = 12 y = 2 (12,2) satifies the equation

There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)

5x27

There are an infinite number of ordered pairs. (-5, -7) is one pair

-2,4

Yes. Yes, it could. So could (0, -1) or (2, 3). Or, if you want, (x, 2x-1).

There are several solutions....what are the choices you have? Guessing one of them is (1,-4) or possibly (-1,-5). --Algebra 2 Teacher

There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.

(-4,-5)