If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
Without an equality sign it can't be considered to be an equation and so therefore it has no solution.
1
If you mean: (-3, 2) and 3x -2y = 5 then it is no because 3(-3) -2(2) = -13
5x-2=13 +2 +2 5x=15 x=3
3x - 2 = 9 3x = 9 + 2 = 11 x = 11/3
If: 3x+6 = 12 Then: x = 2
In the equation 3x plus 7 equals 13, x is equal to 2.
(-3,-4)
If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
That is called "solving for a variable". If there is only one variable in the equation, then it is a "solution". For example, 3x + 4y = 13 can be solved for x as 3x = -4y + 13 x = -(4/3)y + 13/3 This is solved for x. Another equation with only one variable: 5z - 6 = 4 5z = 10 z = 2 This is a solution.
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
Yes
An equation, solution x = -10
The equation 3X take away 11 times 2 equals -2. This is algebra math problem.