Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation and so therefore it has no solution.
If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
Without an equality sign it can't be considered to be an equation and so therefore it has no solution.
1
If you mean: (-3, 2) and 3x -2y = 5 then it is no because 3(-3) -2(2) = -13
5x-2=13 +2 +2 5x=15 x=3
3x - 2 = 9 3x = 9 + 2 = 11 x = 11/3
If: 3x+6 = 12 Then: x = 2
In the equation 3x plus 7 equals 13, x is equal to 2.
(-3,-4)
If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
That is called "solving for a variable". If there is only one variable in the equation, then it is a "solution". For example, 3x + 4y = 13 can be solved for x as 3x = -4y + 13 x = -(4/3)y + 13/3 This is solved for x. Another equation with only one variable: 5z - 6 = 4 5z = 10 z = 2 This is a solution.
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
Yes
An equation, solution x = -10
The equation 3X take away 11 times 2 equals -2. This is algebra math problem.