The area of a triangle is half base times height so any triangles whose base times height is 60 units will have an area of 30 square units e.g.
base = 10 units, height = 6 units;
base = 5 units, height = 12 units;
base = 7.5 units, height = 8 units.
area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides
The area of a triangle is half the base times the height, so obviously the areas will be the same if these figures are identical, but I doubt it is possible to have such correspondence between any two of the triangles you mention! Consider mapping a right triangle to an isosceles - I can't keep the altitude constant.
The area of a square is given by the formula area = width × height. But since the width and height of a square are, by definition, the same, the formula is usually written asarea = s2To determine the length of a side given the area we just have to reverse the formula:s = √areas = √16cm2 = 4cmGiven that the length of each side of a square is the same all we need to do now is multiply the length of a side by the number of sides4cm x 4 = 16cmThe perimeter of a square with an area of 16cm2 is 16cm
yes.
Because the surface areas of 3-d figures are two-dimensional and their measures require square units.Because the surface areas of 3-d figures are two-dimensional and their measures require square units.Because the surface areas of 3-d figures are two-dimensional and their measures require square units.Because the surface areas of 3-d figures are two-dimensional and their measures require square units.
In general, you divide up the polygon into triangles, calculate the areas of the triangles and then sum these.
A=30, B=15, H=4 A=30, B=12, H=5 A=30, B=2, H=30 1/2 b x h= Area
Because it is a branch of mathematics that is concerned with measurements of angles and sides of triangles, and following from that, areas and other characteristics.
Not necessarily. You find the area of a triangle with the formula 1/2*base*height=Area. Imagine two triangles, one with 3 inches for both the base and height, and one with 4.5 inches for the height and 2 inches for the base. Both of these triangles will have 9 sq. in. for their areas, but they are not congruent.
I'll be happy to help you, but in order for me to compare the areas of those triangles, you have to tell me the areas of those triangles.
1 unit and 40 units 100 units and 0.4 units sqrt(2) units and 20*sqrt(2) units.
180, the formula to find areas of triangles is 1/2(bh)
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first divide the hexagon into three parts a rectangle and two triangles then try to findthe areas of all and then take individual heights and add them to get the height of the hexagon
A right angle triangle with two side lengths that match that of an equivalent square will have exactly half the area of the square.
base*perpendicular height = area in square units
There are infinitely many possible answers. Select any number B and let H = 40/B Then a parallelogram with base B and height H has an area of B*H = B*40/B = 40 square units. Since the choice of B was arbitrary, there are an infinity of possible answers.