It is: 6x-4
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(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
you multiply by its denominator to each side. Example: 3x/5=9 now multiply by 5 to each side 3x/5 times 5 is 3x and 9 times 5 is 45 so you get 3x=45 now divide by 3 to each side and you get x=15
Apply the Distrubutive Property twice as you do when multiplying two-digit numbers Use the FOIL methed First Inner Outter Last. In the equation (3x + 4)(9x + 1) you get. (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 Now you multiply. 3x*9x = 27x^2 3x*1 + 9x*4 = 3x + 36x = 39x 1*4 = 4 So your entire answer is (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 = 27x^2 + 39x + 4
Multiply each term of the second expression by each of the terms in the first expression and add them together, collecting like terms together: (x - 6)(3x² + 10x - 1) = x(3x² + 10x - 1) + (-6)(3x² + 10x - 1) = (3x³ + 10x² - x) + (-18x² - 60x + 6) = 3x³ + 10x² - 18x² - x - 60x + 6 = 3x² + (10 - 18)x² + (-1 - 60)x + 6 = 3x² - 8x² - 61x + 6
3x/61 = 7 3x/61 = 7/1 cross multiply 3x = 427 divide by 3 to both sides x = 142.333... x = 142 1/3