(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
you multiply by its denominator to each side. Example: 3x/5=9 now multiply by 5 to each side 3x/5 times 5 is 3x and 9 times 5 is 45 so you get 3x=45 now divide by 3 to each side and you get x=15
Apply the Distrubutive Property twice as you do when multiplying two-digit numbers Use the FOIL methed First Inner Outter Last. In the equation (3x + 4)(9x + 1) you get. (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 Now you multiply. 3x*9x = 27x^2 3x*1 + 9x*4 = 3x + 36x = 39x 1*4 = 4 So your entire answer is (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 = 27x^2 + 39x + 4
Multiply each term of the second expression by each of the terms in the first expression and add them together, collecting like terms together: (x - 6)(3x² + 10x - 1) = x(3x² + 10x - 1) + (-6)(3x² + 10x - 1) = (3x³ + 10x² - x) + (-18x² - 60x + 6) = 3x³ + 10x² - 18x² - x - 60x + 6 = 3x² + (10 - 18)x² + (-1 - 60)x + 6 = 3x² - 8x² - 61x + 6
3x/61 = 7 3x/61 = 7/1 cross multiply 3x = 427 divide by 3 to both sides x = 142.333... x = 142 1/3
5x + 22 = 2x + 76Subtract 2x from each side:3x + 22 = 76Subtract 22 from each side:3x = 54Divide each side by 3:x = 18
Assuming your quesiton is Multiply x times 3x times 4, the answer would be 3x squared times 4.
3x + 16 = 22 3x = 6 x = 6/3 x = 2
-(3x-4) = -3x + 4
It is -24x4.
Since you cannot multiply x by a, in the answer you get ax. 2a * 3x = 6ax
2x(3x-5) = 6x2-10x
If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then (1) y = 22 - 3x (sub this into (2)) (2) (22 - 3x) + 2x = 16 -x = -6 x = 6 y = 22 - 3x = 22 -3(6) = 4 solution: (6,4)
(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
3x = 66 x = 22
It is 22/10*(3x + 2)
3n - 22