58
2a2
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
The height of an equilateral triangle is √3/2 x side_length. So for an equilateral triangle of side length 2a, the area is: area = 1/2 x base x height 1/2 x (2a) x (√3/2 x 2a) = √3 a2
x2=(4a)(a) x=√4a2 x=2a The geometric mean of a and 4a is 2a
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
When you multiply 2a by 2a, you are essentially multiplying 2 by 2 and a by a separately. This results in 4a^2, where the coefficient 4 is the product of 2 and 2, and a^2 represents a multiplied by a. Therefore, the final answer is 4a^2.
x + 2a
Yes. 3X - 2 = -3X^2 add 3X^2 to each side to get in standard form 3X^2 + 3X -2 = 0 Use quadratic equation to solve for X X = -b +/- sqrt(b^2-4ac)/2a a = 3 b = 3 c = -2 X = -3 +/- sqrt[( 3^2 - 4(3)(-2)]/2(3) X = [-3 +/- sqrt(33)]/6 your answer
7a3 = 7 x a x a x a.
2a x 3b = 6ab
x^2 - 3x - 1 = 0 x = -b+-root(b^2 - 4ac)/2a x = 3 +-root(9+4)/2 Two solutions: 1. x = (3+root(13))/2 2. x = (3-root(13))/2
X2+3x-6=0A=1B=3C=-6D=B2-4AC=32-4*1*-6=33X1= (-B+√D)/(2A)=(-3+√33)/(2*6)=1,372281323X2= (-B-√D)/(2A)=(-3-√33)/(2*6)=-4,372281323
58
2a2
3x^2+48x+192=3(x^2+16x+62). You can factor the part in the parentheses using the quadratic formula: x= (-b[+-]Sqrt[b^2-4ac])/(2a).
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.