298 less 209 is 89 209 less 129 is 80 129 less 58 is 71 58 less -4 is 62 The result of each subsequent equation is 9 less than the previous one (89, 80, 71...). The next result is going to be 62-9=53. The first number in each equation above is the same as the second number in the previous equation: 298 less 209 is 89 209 less 129 is 80
So, the next equation will be: -4 less X is 53 Therefore, X is the next number in the original sequence, which resolves to: -57
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Oh, dude, you're throwing some numbers at me like we're playing math dodgeball. So, like, to find the pattern, it's like taking a stroll through a number garden. If you squint real hard, you'll see that we're just subtracting decreasing numbers each time. So, the next number is probably going to be like -4 minus something, but who's really keeping track, right?
The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.
The three numbers are 205, 207 and 209.
The positive integer factors of 418 are: 1, 2, 11, 19, 22, 38, 209, 418
Assuming x(2-10x)=21 to be solved for x, distribute to -10x2+2x=21, or 10x2-2x+21=0. By the quadratic equation, we can determine there are no real solutions because the square root of -836 does not exist. In imaginary solutions, we can reduce to 1/10*(1 + sqrt(-209)) and 1/10*(1-sqrt(-209)) as solutions.