a scale
sine
1+ square root of 5 over 2 not positive
tangent
The ratio is [ 4/x per unit ].
sin θ : 1 = the length of opposite side to angle θ : the length of the hypotenuse
It's called the "scale."
# is the ratio of the demensions in the drawing to the corresponding actual dimensions. The scale factor for a scale drawing is the ratio of the dimensions in the drawing to the corresponding acual bimensions.
It is (or should be) given by the key.
The scale.
The scale indicates how many units of length of the actual object are represented by each unit of length in the drawing.
The scale factor of a scale drawing is the ratio of any length in the drawing to the true corresponding length in the "real" object.
Scale
Mathmatics a drawing with dimensions at a specific ratio relative to the actual size of the object drawn found on http://dictionary.reference.com/browse/Scale%20Drawing Mathmatics a drawing with dimensions at a specific ratio relative to the actual size of the object drawn found on http://dictionary.reference.com/browse/Scale%20Drawing Mathmatics a drawing with dimensions at a specific ratio relative to the actual size of the object drawn found on http://dictionary.reference.com/browse/Scale%20Drawing
To find the scale factor of the drawing, first convert the actual length from feet to inches since the drawing's length is in inches. There are 12 inches in a foot, so 8 feet equals 96 inches. The scale factor can then be calculated by dividing the drawing length (4 inches) by the actual length (96 inches), resulting in a scale factor of 1:24. This means that 1 inch on the drawing represents 24 inches in reality.
If the dimensions of the actual playground are 50 times those of the scale drawing, then the length and width of the actual playground can be represented as 50 times the length and width of the scale drawing. The area of a rectangle is calculated by multiplying length by width. Since the area of the scale drawing is 6 square feet, the area of the actual playground will be ( (50 \times \text{length}) \times (50 \times \text{width}) = 2500 \times \text{(length} \times \text{width)} ). Therefore, the area of the actual playground is ( 2500 \times 6 = 15,000 ) square feet.
25cm = 1m1cm = 0.04m = 4cm0.1cm = 0.004m = 0.4cm4 + 0.4 = 4.4cm
24.75 ft.