Sure. The other two angles would then be 20 each.
The sum of the angles is 180 degrees in any triangle. So 180-140 is 40 and the third angle is 40 degrees.
A = 60 B = 20 C = 140 This can have a large number of answers.
The angle sum of any polygon is 360 degrees.
Providing that it is a regular nonagon then each exterior angle measures 40 degrees and each interior angle measures 140 degrees
Obtuse Triangle
Yes. The angle that is not the same can be 140 degrees. Because the other two angles are equal, then they would both be 20 degrees.
Sure. The other two angles would then be 20 each.
No, not really. The two remaining interior angles have to add up to 90, since the sum of the angles in a triangle must total 180. The right angle means you have already used 90, so the remaining two must have a sum of 90. There is a more complex answer. Right triangles can have an external angle of 140. If angle A is 90 degrees, and angle B is 40 degrees, then angle C will be 50 degrees. The external angle at the extension of AB, through corner B, namely the extension of a ray from A through B, will create an angle with segment CB. It will be the sum of the measures of A and C: 140 degrees.
A 140 degree angle is about half way between a 90 degree angle, which has lines that are perpendicular to each other, and a 180 degree angle, which is a straight line. A 140 degree angle is an obtuse angle which has a line a little over half way between the 90 degree and 180 degree angles.
A 140 degree angle would be called an obtuse angle.
Unless you are ready for some complicated trigonometry, I would suggest that you use a protractor and draw a 50 degree angle BEYOND a right angle.
60
The sum of the angles is 180 degrees in any triangle. So 180-140 is 40 and the third angle is 40 degrees.
140 degrees
No angle can be complementary to a 140 degree angle, as the sum of complementary angles is 90 degrees. But angles which are supplementary to each other add together to form a 180 degree angle.
40 degrees ( 180 - 140 = 40 )