x2-5x+4 = (x-1)(x-4) when factord
x2-5x = 24 x2-5x-24 = 0 (x-8)(x+3) = 0 x = 8 or x -3
The question cannot be answered because there is no inequality there!
If x2 < 25 Then: |x| < 5 -5 < x < 5
-x2+2x
x^(2) + 3x - 7 = 5x + 8 Subtract '8' from both sides Hence x^(2) + 3x - 15 = 5x Subtract '5x' from both sides Hence x^(2) -2x - 15 = 0 It is now in quadratic form and will factor. Hence ( x -5)(x + 3) = 0 x = 5 & x = -3
If you mean: x2+5x+6 = 0 then the solutions are x = -3 and x = -2
x2 + 5x - 120 can not be factored.
x2 + 5x + 6 = (x + 2)(x + 3)
2x + 5x = 7x
x2≤64
x2 - 5x + 6 = (x - 2)(x - 3)
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x+6 = (x+2)(x+3)
5x+x >100
5(x2 + x + 1)