4x + 3y = 8x + y
so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
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4x+3y = 12 3y = -4x+12 y = -4/3x+4
4x+3/3=y
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
Presumably this is a simultaneous equation in the form of: -4x+3y = 27 -2x+y = -1 Multiply all terms of the bottom equation by 2: -4x+3y = 27 -4x+2y = -2 Subtract the bottom equation from the top equation remembering that a - - is equal to a + Meaning that -4x - -4x = 0 and 27 - -2 = 29: So y will = 29 Substitute the value of y into the original equations to find the value of x Therefore: x = 15 and y = 29
4x + 3y + 3 = 4 ----> 4x = 1 - 3y ----> x = 0.25 - 0.75y ----> 3y = 1 - 4x ----> y = (1/3) - (4/3)x