5x+3y
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
3y - 4x = 24 The first step is to write it in the standard form (y=mx + c) 3y = 4x + 24 y = (4x + 24)/3 y = 4x/3 + 8 The y-intercept is 8 and the slope/gradient is 4/3
4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3
4x+3y = 3 3y = -4x+3 y = -4/3x+1 in slope intercept form
4x+3y = 12 3y = -4x+12 y = -4/3x+4
4x = -3y+8 3y = -4x+8 y = -4/3x+8/3 So the slope is -4/3 or -1 and a 1/3
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
7
4x + 3y = 7 y = [(-4)/3] x + 7/3
If: -4x+3y = 1 Then: 3y = 4x+1 And: y = 4/3x+1/3 which is now in slope-intercept form
5x+3y
The gradient (slope) of 3y = 4x+5 is 4/33y = 4x+5y = 4/3x+5/3y=mx+c(m = gradient)mx+c = 4/3x+5/3m = 4/3
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
-4x + 3y = 9
3y = 4x + 9 -4x + 3y = 9 is the standard form