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(2,3)
x+2(x+3) = 12 x+2x+6 = 12 x+2x = 12-6 3x = 6 x = 2 and y = 5
x=6y-4x=-2y+28Substitute (6y-4) for x in the second equation and solve for y:6y-4=-2y+288y=32y=4Then solve for x:x=6(4)-4=20(20,4)
X = 135 and y = 15 Solved by addition and substitution
x=b-a