Given: x2 + 10x - 16
Let: x2 + 10x - 16 = 0
x2 + 10x - 16 = 0
∴ x2 + 10x + 25 = 16 + 25
∴ (x + 5)2 = 41
∴ x = -5 ± √41
∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
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x2-64 = (x-8)(x+8)
x2 + 10x + 25 --> (x + 5)2
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
If that's + 10x + 21, the answer is (x + 7)(x + 3)
x2-10x-24 = (x+2)(x-12) when factored