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Given: x2 + 10x - 16

Let: x2 + 10x - 16 = 0

x2 + 10x - 16 = 0

∴ x2 + 10x + 25 = 16 + 25

∴ (x + 5)2 = 41

∴ x = -5 ± √41

∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)

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15y ago

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