y = 5x - 4 Substitute 6 in for y; then solve for x: 6 = 5x -4 10 = 5x 2 = x So, the x-coordinate is 2.
5x-2 = 3x-6 5x = 3x - 6 +2 5x = 3x - 4 5x - 3x = -4 2x = -4 x = -2
How to solve: 5x+2=27 5x=25 (Subtract 2 from each side) x=25/5=5 (Divide each side by 5) So, x=5
1. If the question is only to factor this expression:x^2 + 5x = x(x + 5)2. If the question is to solve the equation x^2 + 5x = 0:x^2 + 5x = 0 factor it;x(x + 5) = 0x = 0 orx + 5 =0 subtract 5 to both sides;x = - 5
5x-3 = 11+12x 5x-12x = 11+3 -7x = 14 x = -2
Expression: x+10+5x Solve: x+5x=6x Answer: 6x+10
It's impossible to solve x 5x over 10 2, as the equation doesn't make sense the way it's structured.
X intercept is where it intersects the X-axis, which is where y = 0. So set y=0 in the equation, and solve for x. 5x - 2(0) = 10 --> 5x = 10 --> x = 2. So the point (2,0) is where the x-intercept is.
5x+2=x+10 5x-x=10-2 4x=8 x=2
-5x + 30 = 20 -5x + 30 - 30 = 20 - 30 -5x = -10 -5x / -5 = -10 / -5 x = 2
To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
y = 5x - 4 Substitute 6 in for y; then solve for x: 6 = 5x -4 10 = 5x 2 = x So, the x-coordinate is 2.
5x+7 = 2x-3 5x-2x = -3-7 3x = -10 x = -10/3
5x=10 5x/5=10/5 x=2
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
7X-1=9+5X. add 1 to both sides 7X=10+5X. Subtract 5X and get 2X=10 divide by 2 and x=5