1. If the question is only to factor this expression:
x^2 + 5x = x(x + 5)
2. If the question is to solve the equation x^2 + 5x = 0:
x^2 + 5x = 0 factor it;
x(x + 5) = 0
x = 0 or
x + 5 =0 subtract 5 to both sides;
x = - 5
(5x + 2)(x + 3)
(x - 1)(5x + 7)
That factors to (x - 2)(x + 7)
5x cubed
x^(2) + 5x^(2) = 6x^(2) Think of it as 2 + 5(2) = 6(2) ( 2 + 10 = 12 = 6(2)) Note : You just add the coefficients(numbers)/. However, be careful and note the difference for multiplication. x^(2) X 5x^(2) = 5x^(4) ( That is 'five 'x' to the fourth power'). In this case x^(2) means x X x and 5x^(2) = 5 X x X x , so on multiplication it becomes 5 X x X x X x X x = 5x^(4)
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
(5x + 2)(x + 3)
5(x2 + x + 1)
5x2+56xy+11y2 = (5x+y)(x+11y) when factored
(x + 3)(x + 2)
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
No.
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
The question contains an expression. An expression does not have an answer - it cannot be solved.
(x - 1)(5x + 7)
(5x - 2)(x - 5)