If r-squared = theta then r = ±sqrt(theta)
So u have the function x2-4=0 Now because 4 is a squared number, its square root is 2 (x+2)(x-2)=0
X=1
Equals divided by non-zero equals are equal.
5b2 = 8b therefore 5b =8 therefore b = 1.6
If x squared -10 = 0 then x = the square root of 10
Square root both sides and then x = 4
If x squared equals n, then x is the square root of n.
Solve this problem -x squared -40x- 80 =0
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
5.
Yes and x = 2+square root of 6 or x = 2-square root of 6
If r-squared = theta then r = ±sqrt(theta)
root 7
h = +11 and/or -11
-2y square exp power -2x-1