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P'(x) = -10x + 600 To maximise equation, let P'(x) = 0 Therefore, 0 = -10x + 600 10x = 600 x = 60 Therefore, 60 items must be sold in order to maximise profits. I hope this has helped! ^.^

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Q: Suppose that the equation px -5x2 600x 100 where x represents the number of items sold describes the profit function for a certain business How many items should be sold to maximize the pro?
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If the function is a straight line equation that passes through the graph once, then that's a function, anything on a graph is a relation!


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