breadth = 4x - 10 ie length + breadth = 5x - 10.
Perimeter is double this figure ie 10x - 20 or 10(x - 2)
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)
let p represent perimeter let w rep. width let l rep. length p = 2l + 2w --> basic perimeter formula l = w + 2 --> two feet more than width 20 = 2(w + 2) + 2w --> sub w + 2 in for l and 20 in for p (given in question) 20 = 2w + 4 + 2w 20 = 4w + 4 --> group like terms 16 = 4w 4 = w if your looking for the width it's therefore 4 feet. and for the length: l = w + 2 l = 4 + 2 l = 6 therefpre the length is 6 feet.
Let x = width of the box. We know that the length = 3x, and that the perimeter is 2*length + 2*width, thus we have the equation 2*(3x) + 2*x = 64 => 6x+2x = 64 Combining like terms: => 8x = 64 Solving for x by dividing both sides by 8: x=8 Thus we know that the width is 8, and length = 3*x =3*8 = 24 Area = width*length = 8*24 = 192
A golden rectangle is a rectangle where the ratio of the length of the short side to the length of the long side is proportional to the ratio of the length of the long side to the length of the short side plus the length of the long side. It is said to have the "most pleasing" shape or proportion of any rectangle. The math is like this, with the short side = s and the long side = l : s/l = l/s+l Links can be found below to check facts and learn more. In ratio terms, the Golden Rectangle has a width/height ratio of 1.618/1.
The formula for the perimeter of a rectangle is: p = 2(l + w) In other words, just add all four sides. You can't calculate the perimeter of the rectangle if you know only the length.
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
Measure the length and breadth of one face of the rectangle. Measure the thickness of the rectangle hollow piece. Multiply the length, breadth and thickness and this will give you the volume of the rectangular hollow piece in terms of cubic units. That is, if you measured the length, breadth and height in centimeters, the volume will be in cubic centimeters. Example: If the length of the piece is 10 cm, the breadth of the piece is 6 cm, and the thickness of the piece is 5 cm, the volume of the rectangular hollow piece is given by: 10 cm X 6 cm X 5 cm = 300 cubic cm or cm3
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.
Suppose the other side of the rectangle is y, then perimeter = 2(length + breadth) so 20 = 2*(x+y) so that x+y = 10 or y = 10-x Then, A = x*y = x*(10-x) or 10x - x2 Note that x>0, y>0 require that 0<x<10. The function is not defined outside these limits for x.
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
Length and Breath are terms used in golf. Length is the longevity of your swing, back to front. Breath is your breathing pattern during a swing, which should be kept constant.
A perimeter is a length. It cannot be expressed in terms of area.
Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)
First, let's call the length of the rectangle L, and the width W.We know that the length is 8 more than the width, i.eL = W+8Now we also know that the perimeter of a rectangle is P=2L+2W, where the P in this case is would be 24.Which gives us 2 equations;L = W+8 [1]24=2L+2W [2]Using simultaneous equations, lets find the perimeter in terms of W, by substituting in the value of L in equation [1]24 = 2(W+8)+2WExpand:24 = 2W+16+2WSimplify:4W + 16 = 24Subtract 16 from both sides:4W = 8W = 2Now substitute W=2 into [1]:L = 2+8L = 10Therefore:The length and width of the rectangle are 10 units and 2 units respectively.
3