The distance from point A to point B on a grid is a vector?

The distance from point A to point B on a grid is scalar or vector?

VECTOR

The distance from point A to point B on a grid?

Vector

What type of measurement is thisthe distance from point A to point B on a grid?

Length.

The distance from point a to b on a grid?

The answer depends on the grid. On the taxicab grid, which was studied by Minkowski, the distance is the sum of the vertical and horizontal distances between a and b. See, for example, https://en.wikipedia.org/wiki/Taxicab_geometryIf, a and b have horizontal and vertical coordinates which are, respectively, (xa, ya) and (xb, yb) then the grid distance is abs(xa - ya) + abs(xb - yb).

What is the difference between distance an displacement?

A distance is the length of the straight line path between 2 points. This is also known as a scalar value as it has a magnitude but no direction. A displacement is the distance and the direction between one point and another. This is also known as a vector as it has magnitude and direction as well. Note that the distance between two points, say, point A and point B is the same as the distance from point B to point A. It remains the same value regardless of the direction of travel. On the other hand, if a displacement between point A and point B was 1 mile North, it cannot be reversed. The displacement between point B and point A is 1 mile South - the same distance but an opposite direction.

How do you prove using a diagram that the magnitude of the sum of two vectors is less than or equal to the sum of the magnitude of the two vectors?

You could draw a circle [center at origin] with radius of (a + b), for the two magnitudes a and b. This represents the sum of the magnitudes. Then draw one of the vectors starting at the origin [suppose it's vector a], and then draw a circle centered at the endpoint of vector a, with a radius of b. Drawing a circle demonstrates how the second vector can point in any direction relative to the first vector. The distance from the origin to a point on this second circle is the magnitude of the resultant vector. Graphically this second circle will be entirely inside the first circle and touching it at just one point. Since it lies within the first circle, the distance from the origin to a point on that circle will be less than or equal to the radius of the first circle.

If i have a points a and b in 3d space and i want to move b n units closer to a how do i determine how much to change b's x y and z values?

How to move a specific distance along a line determined by 2 points in 3d space! Specific distance = m Distance between the 2 points = D Distance to move along line from Point #2 toward Point #1 = Displacement = m Determine the coordinates of the point M (c, d, e), which is m units closer to Point#2 Given 2 points Point #1 (a, b, c) Point #2 (g. h, i) 1. Find the distance between the 2 points using Pythagorean Theorem Think of moving from Point #1 to Point #2 by moving along the x-axis, then the y-axis, then the z-axis. (g-a) = distance moved along the x-axis (h-b) = distance moved along the y-axis (i-c) = distance moved along the x-axisS D = [(g-a)^2 + (h-e)^2 + (i-c)^2]^0.5 2. Determine the coordinates of the unit vector by dividing the distance moved along each axis by D. Coordinates of unit vector = [(g-a) ÷ D], [(h-b) ÷ D], [(i-c) ÷ D] x coordinate of unit vector = (g-a) ÷ D y coordinate of unit vector = (h-b) ÷ D z coordinate of unit vector = (i-c) ÷ D Unit vector = [((g-a) ÷ D)^2 + ((h-e) ÷ D) ^2) + ((i-c) ÷ D) ^2]^0.5) = 1 If the value of the unit vector does not =1, go back and check your work. 3. Multiply each coordinate of the unit vector by m to determine the coordinates of the vector m. These coordinates will be added to coordinates of Point #1 to determine the coordinates of Point #3. x coordinate of m vector = m * (g-a) ÷ D y coordinate of m vector = m * (h-b) ÷ D z coordinate of m vector = m * (i-c) ÷ D 4. To determine the coordinates of Point #3(d, e, f) that is m cm from Point #1 toward Point #2, add the coordinates of the m vector to the coordinates of Point #1. d = x coordinate of Point #3 = a + (m * (g-a) ÷ D) e = y coordinate of Point #3 = b + (m * (h-b) ÷ D) f = z coordinate of Point #3 = c + (m * (i-c) ÷ D) 5. To determine the distance from Point #1 (a, b, c) to Point #3 (d, e, f), use Pythagorean Theorem D = [(d-a)^2 + (e-b)^2 + (f-c)^2]^0.5 The answer should be m. I wanted to move 2 cm from Point #1 toward Point #2, and I did. Now let's see if this method works!! Point #1 = (2,3,1), Point #2 = (6,9,3) I want to move 2 cm from Point #1 toward Point #2, that means m = 2 cm. 1. Find the distance between the 2 points using Pythagorean Theorem D = [(g-a)^2 + (h-e)^2 + (i-c)^2]^0.5 D = [(6-2)^2 + (9-3)^2 + (3-1)^2]^0.5 D = [(4)^2 + (6)^2 + (2)^2]^0.5 D = [16 + 36 + (4)]^0.5 D = 56^0.5 D = 7.4833 So the line between these Point #1 and Point #2 is 7.483 units long 2. Determine the coordinates of the unit vector by dividing the distance moved along each axis by D. Distance moved along x-axis = 4 Distance moved along y-axis = 6 Distance moved along z-axis = 2 x-coordinate of unit vector = 4 ÷ 7.4833 = 0.5345 y-coordinate of unit vector = 6 ÷ 7.483 = 0.8018 z-coordinate of unit vector = 2 ÷ 7.483 = 0.2673 Length of unit vector = [(0.5345)^2 + (0.8018)^2+ (0.2673)^2]^0.5 = 1 The length of the unit vector should = 1 3. Multiply each coordinate of the unit vector by m to determine the coordinates of the vector m. x coordinate of m vector = m * (g-a) ÷ D = 2 * 0.5345 = 1.069 y coordinate of m vector = m * (h-b) ÷ D = 2 * 0.8018 = 1.6036 z coordinate of m vector = m * (i-c) ÷ D = 2 * 0.2673 = 0.5346 m vector = [1.069^2 + (1.6036)^2 + (1.5346)^2]^0.5 = 2 4. To determine the coordinates of the Point #3 (d, e, f) that is m cm from Point #1 toward Point #2, add the coordinates of the m vector to the coordinates of Point #1 (a, b, c). Point #1 = (2, 3, 1) x coordinate of Point #3 = 2 + 1.069 = 3.069 y coordinate of Point #3 = 3 +1.6036 = 4.6036 z coordinate of Point #3 = 1+ 0.5346 = 1.5346 Point #3 = (3.069, 4.6036, 1.5346) 5. To determine the distance from Point#1 to Point #3, use Pythagorean Theorem D = [(d-a)^2 + (e-b)^2 + (f-c)^2]^0.5 D = [(3.069-2)^2 + (4.6036-3)^2 + (1.5346-1)^2]^0.5 D = [(1.069)^2 + (1.6036)^2 + (0.5346)^2]^0.5 = 2 D = 2 cm I wanted to move 2 cm from Point #1 toward Point #2, and I did.

What is driving distance?

The distance from point A to point B when you are driving on roads.

What is the distance from point A to point B in decimal form?

The answer depends on where A and B are.

What is the angle between vector a and vector b when mode of vector a plus vector b is equal to mode of vector a minus vector b?

90 degrees

Is it possible for vector A plus vector B to equal vector A - vector B?

It's impossible as the addition of two vectors is commutative i.e. A+B = B+A.For subtraction of two vectors, you have to subtract a vector B from vector A.The subtraction of the vector B from A is equivalent to the addition of (-B) with A, i.e. A-B = A+(-B).

The distance from point A to point B on a grid is a vector?

Add your answer:

What type of measurement is thisthe distance from point A to point B on a grid?

What algebraic expression shows the square of the distance from point A to point B minus 81?

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The distance from point A to point B on a grid is scalar or vector?