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Q: How do i find the perimeter of a rectangle if you know its length and its width?

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The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

you need length and width length multiply width = area length + length + width + width = perimeter

Length + length + width + width = perimeter. Length + width x 2 = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

You divide the perimeter by the width and you get the lenght

Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length

Length = (Perimeter - twice width) / 2

2*length + 2*width

by appying 2l+2w

length 18 width 7

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