2(L+W)=P
2(W+4+W)=56
4W+8=56
4W=48
W=12
Length is 16
length = 22 meters and width = 6 meters
14 cm
Let the length be 2x-3 and the width be x:- So: 2*(2x-3+x) = 82 feet => 6x-6 = 82 => x = 14 and 2/3 Therefore the dimensions are: length = 26 ft 4 ins and width = 14 ft 8 ins
the perimeter of a rectangular rug is 40 ft. the length is 2 ft longer than the width. find the dimensions
Let the width be x, so the length is 2x - 4. Since one half of the perimeter is 26 feet ( 52/2), then we have:x + (2x - 4) = 263x - 4 = 263x - 4 + 4 = 26 + 43x = 303x/3 = 30/3x = 102x - 4 = 2(10) - 4 = 20 - 4 = 16Thus the width of the rectangular garden is 10 feet, and the length is 16 feet.
divide perimeter by 6.
The dimensions are 12 feet by 4 feet
length = 22 meters and width = 6 meters
the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
14 cm
28
Only one way to find out: measure the width and the length of the garden, add them together and multiply by two which gives the perimeter of the rectangular garden.
14 feet (14+14+28+28 = 84)
Width = 16 feet Length = 38 feet
6 feet 6+6+4+4 = 20
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