This has infinite no. of solutions.
If you mean points: (2, 5) and (9, 2) then it works out as y = -3/7x+41/7
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
sqrt(41) cannot be simplified so it remains radical(41).
Points: (0.3, -0.5) and (0.8, -0.1) Distance: square root of 41 over 10 which is about 0.64 to two decimal places
sqrt(656) = sqrt(16*41) = sqrt(16)*sqrt(41) = 4*sqrt(41)
The Tropic of Capricorn passes through Botswana.
If you mean points of: (-5, -39) and (10, 84) then the slope works out as 41/5 which is the same as 8.2
If you mean points: (2, 5) and (9, 2) then it works out as y = -3/7x+41/7
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
The equation of the circle works out as: (x+2)^2 + (y-5)^2 = 41 The circle's centre is at: (-2, 5) Its radius is the square root of 41
% rate = 41/75 * 100% = 54.67%
To find the equation of the line passing through the points (4, 7) and (-2, 6), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{6 - 7}{-2 - 4} = \frac{-1}{-6} = \frac{1}{6} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (4, 7), the equation becomes ( y - 7 = \frac{1}{6}(x - 4) ). Simplifying, we can express the equation as ( y = \frac{1}{6}x + \frac{41}{6} ).
Using the formula x^2 +2gx +y^2 +2fy +c = 0 the equation of the circle works out as (x+2)^2 +(y-5)^2 = 41
Points: (40, -64) and (41, -35) Slope: 29
41
41 weight watchers points plus
Equations: x2+2x-7 = 17-3x Quadratic equation: x2+5x-24 = 0 Points of intersection: (-8, 41) and (3, 8) Length of line: (-8-3)2+(41-8)2 = 1210 and the square root of this is the length of the line which is about 34.78505426 or to be exact it is 11 times the square root of 10.