To find the equation of the line passing through the points (4, 7) and (-2, 6), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{6 - 7}{-2 - 4} = \frac{-1}{-6} = \frac{1}{6} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (4, 7), the equation becomes ( y - 7 = \frac{1}{6}(x - 4) ). Simplifying, we can express the equation as ( y = \frac{1}{6}x + \frac{41}{6} ).
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
It is y = 2.
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
Answer this question…y = 2x + 6
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
It is y = 2.
Y= -3x + 8
If the line passes through (5, 2) and (5, 7), then the x value stays constant for those two points, and since it is a line, the x value stays constant for the whole line, so the equation of the line isx = 5
3
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
Answer this question…y = 2x + 6