4 inches wide, 11 inches long.
11(length) -4(width) = 7
11*2 = 22 (2 long sides)
4*2 = 8 (2 short sides)
total sides = 30
this one is not too difficult to do in your head, but for similar problems you can use a system of equations.
x + 7 = y
2x +2y = 30
(x is width, y is length)
P=2(L+W)=7+W+W=7+2W
2W=30-7=23
W=23/2=11.5 SORRY INCORRECT WORKING OUT THE ABOVE IS CORRECT (sorry about the shouting)
the perimeter of a triangle is 86 inches. the largest side is four inches less than twice the smallest side. the third side is 10 inches longer than the smallest side. what is the length of each side?
If the width is seven on both sides and the length is seven on both sides then the perimeter is 7+7+7+7 = 28.
The length of each side is seven (7) meters.
The easiest way to reason this is to consider how you could connect nine squares together while leaving the largest amount of perimeter exposed. In other words, what's the largest number of faces you can leave exposed on a set of squares that are all connected? The answer is that if you connect all of the squares in a line, then the two end squares will have three faces exposed and the other seven squares will have two faces exposed. That gives you 2 * 7 * 2cm + 3 * 2 * 2cm = 28cm + 12cm = 40cm. So the maximum perimeter you can get is 40cm. There are many other ways that you can arrange the squares to give you the same perimeter (eg. a plus sign, a zig-zag, and so on), but none that will give you more.
Basically, this is the same as finding the number of distinct ways of arranging seven 1s and 3 0s. That is (10!/7!3!) = (10*9*8)/(3*2*1) = 120. There are 120 bit strings of length 10 with exactly three 0s.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
Seven 9 inch squares placed end to end would form a rectangle that was still 9 inches wide but 7 x 9 = 63 inches long. The distance around such a rectangle would measure its perimeter. Two sides are 9 inches long and two sides are 63 inches long. The perimeter would be 63 + 63 + 9 + 9 = 144 inches.
A heptagon is a shape that has seven sides of equal length. The perimeter of a heptagon can be found by multiplying the length of one side by seven. * * * * * No! The perimeter is the sum of the lengths of the seven sides. There is absolutely no requirement for the seven sides to be of equal length!
the perimeter of a triangle is 86 inches. the largest side is four inches less than twice the smallest side. the third side is 10 inches longer than the smallest side. what is the length of each side?
If the width is seven on both sides and the length is seven on both sides then the perimeter is 7+7+7+7 = 28.
seven inches
Seven to eight inches in length.
Seven inches.
The Perimeter of a shape can be found by adding the sides of said shape together. In the case of a Pentagon (five sided shape) you can simply multiply the known seven inches per side, by five. This leaves you with 35inches as your perimeter.
They are between three and seven inches in length.
You add the lengths of all the sides. If the sides happen to be of equal length, you multiply this length by 7.
A rectangle is a geometric shape having four sides and four right angles. Here are some sentences.A football field is a rectangle.The rectangle measured three inches by seven inches.A square is a type of rectangle with equal sides.