5,12,13
shorter side = 10 longer side = 19
Solve the problem in stages:Solve for the length of the triangle side.Perimeter = sum of all the sides. As equilateral, all sides equal so 3 x side_length = 90 inside_length = 90in / 3 = 30in.Pentagon side is triangle_side + 2in, thus Pentagon_side = 30in + 2in = 32inThere are 5 sides to a pentagon, each 32in long, so its perimeter is 5 x 32in = 160in.
x+4+x+2+x = 24 3x+6 = 24 3x = 24-6 3x = 18 x = 6 longest side = 10 inches
The minimum perimeter is when the triangle is an equilateral triangle. The perimeter of any other triangle with the same area will be longer. In the case of an equilateral triangle area = (√3)/4 × side² → side = √(4×6.5 cm²/√3) → perimeter = 3 × side = 3 × √(4×6.5 cm²/√3) ≈ 11.62 cm → The triangle has a perimeter greater than or equal to approx 11.62 cm.
Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
13, 12,5
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.
the perimeter of a triangle is 86 inches. the largest side is four inches less than twice the smallest side. the third side is 10 inches longer than the smallest side. what is the length of each side?
Let x be the side of the triangle. Thus 4(x-5) is the perimeter of the square.Balance by the perimeter relation,3x = 7+4(x-5)Solve for x,x = 13 inches
Length + width = half of perimeter = 37 in. 37 - 9 = 28, half of 28 = 14 which is the width, and the length is 23
Let the base length be x:- If: 2(0.5x+9)+x = 146 => x+18+x = 146 => 2x = 146-18 => x = 64 Therefore the isosceles triangle has 2 equal sides of 41 inches and a base of 64 inches Check: 41+41+64 = 146 inches
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
One possibility is an irregular triangle with a side of 5 units.
Hz
Length of longer leg = 9.4 tan 60 = 16.28 feet Length of hypotenuse = 9.4 ÷ cos 60 = 18.8 feet Perimeter of triangle = 9.4 + 16.28 + 18.8 = 44.48 feet
shorter side = 10 longer side = 19
The perimeter actually doesn't tell you anything about the breakdown betweenthe length and width. All we can tell about this one is that the sum of (length+width)has to be 98 inches. That still leaves an infinite number of possible rectangles.If the perimeter is 196 inches and the length has to be the longer dimension, thenit can be anything more than 49 inches, with no upper limit.For example:Width = 1 millionth of an inchLength = 1 millionth of an inch less than 98 inchesPerimeter = 196 inches.