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Yes, your statement is dimensionally correct. But your formula is incorrect, and possibly ambiguous. First, the perimeter is only a simple sum involving length and width IF the figure is a rectangle. Second, the perimeter of the rectangle is double what you have stated: P = 2L + 2W
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How do you find width when you have perimeter and length?
width = (perimeter-2*length)/2
How do you find breadth using perimeter and length?
If the shape is a rectangle (or square), then Perimeter = 2*(Length + Breadth) So Breadth = Perimeter/2 - Length
If the perimeter is 48 If the length is twic the width what is the length of rectangle?
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
How do you find the perimeter of a regular nonagon?
The answer depends on what information you have. If you have the length of a side, then the perimeter is nine times that length.
