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Designate the radius by r and the height by h. For any cylinder, volume = 2 X pi X r X h. From the problem statement, h = 7/5 r. Substituting this into the general volume equation yields 2 X pi X r X (7/5)r = volume (stated to be 550 cm3). Multiplying by 5 and collecting like terms yields 2 X pi X 7 r2 = 2750; r2 = 2750/[(2)(pi)(7)] = about 62.526; r = about 7. 9 cm.

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What is the radius ratio of SC and Bcc and FCC?

Radius ratio of FCC is 1.0 and of BCC is 0.732


How do you solve this question Two spheres are cut from a certain uniform rock One has radius 4.50 cm The mass of the other is five times greater Calculate its radius?

Since volume = 1/density x mass and as the rock is uniform it has a constant density, the volume is directly related to the mass; meaning that since the mass of the second is 5 times as big as that of the first, the volume of the second is also 5 times as big as that of the first. The ratio of volumes is the cube of the ratio of lengths; so the lengths are in the ratio of the cube root of the ratio of the volumes. The ratio of the volumes in this case is 1:5 giving the ratio of the lengths as 1:3√5 So the second radius is 3√5 (≈ 1.71) times as big as the first, making it 4.50 cm x 3√5 ≈ 7.69 cm.


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Related Questions

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