x+(x+2)+(x+4)+(x+6)=2164x+12=2164x=204x=51the integers are 51, 53, 55, and 57
The numbers are 215, 216, 217 and 218.
The numbers are 215, 216, 217, and 218.
The idea is to find a number which, when cubed, gives you 216. This can quickly be found with trial and error, since 216 happens to be a perfect cube.
216
The integers are 51, 53, 55 and 57.
The largest is 73.
220
x+(x+2)+(x+4)+(x+6)=2164x+12=2164x=204x=51the integers are 51, 53, 55, and 57
108, 162, 216 & 270
The numbers are 215, 216, 217 and 218.
The numbers are 215, 216, 217, and 218.
215 + 216 + 217 + 218 = 866
For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.
the sum of three consecutive numbers is 216. What are the three numbers?
x+x+1+x+2=216 3x+3=216 3x=213 71,72,73
71,72,73 :)