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We get a system of equations:

a+b=12

a2+b2=90.

Replace 12-a for b, and we get:

a2+(12-a)2=90

2a2-24a+144=90

2a2-24a+54=0

a2-12a+27=0

a1=9

a2=3

Because of symmetry, we get two equivalent solutions:

a=9, b=3

or

a=3,b=9

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15y ago
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lenpollock

Lvl 15
1y ago

Let the numbers be l & m .

Hence

Sum l + m = 12

Sum of the squares is l^2 + m^2 = 90

Hemce

l = 12 - m

l^2 = ( 12 - m)^2

l^2 = 144 - 24m + m^2

Substitute

144 - 24m + m^2 + m^2 = 90

2m^2 - 24m = -54

m^2 - 12m = -27

m^2 - 12m + 27 = 0

Factor

(m - 3)(m - 9) =0

m = 3 & m = 9 are the two numbers.

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Q: The sum of two numbers is 12. The sum of the squares of the same two numbers is 90. What are the two numbers?
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