Set up a system of equations. Let the numbers be x, y. X + Y = 15
3X = 5Y-11 Solve the first equation for Y.
Y = 15-X
Plug it into the second equation.
3X = 5(15-X) - 11
And solve for X.
3X = 75 - 5X - 11
3X = 64 - 5X
8X = 64
X = 8 Plug X back into the original first equation.
8 + Y = 15
Y = 7 X = 8, Y = 7
The last digit must be odd: three possibilities. The other digits can be anything else, as long as they're different: five times four times three possibilities. Thus, the answer is 3 x 5 x 4 x 3 = 180.
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The numbers are 10 and 5
Mrs Cruz is 27 and her son is 3.
divide 45 by 5 and multiply by 3 45 divided by 5 is 7 times 3 is 21.
9 and 10
26+7
Five times thirty-three is equal to 165.
The numbers are: 3 and 12
11
Assuming that you can use each number multiple times, 3125, because there are five options for the first number, five for the second, and so on to reach five. Then, five times five times five times five times five, or five to the fifth power, equals 3125. Were you only able to use each number once, the answer would be 120 based on the same principle. There would be five options for the first number, four remaining options for the second, three for the third, two for the fourth, and then one for the fifth. Then, as with the first, five times four times three times two (times one, but that really isn't necessary) results in 120.
There are 27 numbers between 1 and 100 that are divisible by three but not by five.
Five ninths times three fifths is one third.
Three times five equal 15 all u need to do is count by five 5,10,15
Eight times twenty-five times twenty-three is equal to 4,600.
what is divisible by two,three,four,five and ten
44