0
How many odd numbers with 4 distinct digits can be formed using the digits in 234567?
Wiki User
∙ 15y ago
The last digit must be odd: three possibilities. The other digits can be anything else, as long as they're different: five times four times three possibilities. Thus, the answer is 3 x 5 x 4 x 3 = 180.
Wiki User
∙ 15y ago
Add your answer:
Earn +20 pts
How many 3 digit numbers can be formed using the digits 2 3 5 6 7 9 if repetition of digits is not allowed?
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
How many different 2 digit odd numbers can be formed from the digits 1 through 8 if no digits are repeated in a number?
36
How many 8 digit numbers can be formed by the digits 1234567890?
u culd make 80
How many 6 digit numbers can be formed with 4 different digits?
The question can be re-stated as asking for the total number of permutations that can be derived from the following two groups of digits: AAABCD and AABBCD, where A, B, C and D are different. The number of ways of choosing the digit A, to be used three times, out of the ten digits {0, 1, 2, ... 9} is 10. Having done that, the number of ways of selecting 3 from the remaining 9 digits is 9C3 = (9*8*7)/(3*2*1) = 84. Thus there are 10*84 = 840 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 3 of the digits are the same, these permutations are not all distinct. In fact, there are 6!/3! = 120 distinct permutations. That makes a total of 840*120 = 100800 such numbers. Next, the number of ways of choosing the digits A and B, each to be used twice, out of the ten digits {0, 1, 2, ... 9} is 10C2 = (10*9)/(2*1) = 45. Having done that, the number of ways of selecting C and D from the remaining 8 digits is 8C2 = (8*7)/(2*1) = 28. Thus there are 45*28 = 1260 combinations of the form AAABCD. You now need all the distinct permutations of these 6 digits. The total number of permutations of 6 digits is 6! but because 2 pairs of these digits are the same, these permutations are not all distinct. In fact, there are 6!/(2!*2!) = 180 distinct permutations. That makes a total of 1260*180 = 226800 such numbers. The grand total is, therefore, 100800 + 226800 = 327600 6-digit numbers made from 4 distinct digits.
How many 4 digit numbers can be formed by the digits 1234567890?
The number 1234567890 can create about 39 of 40 4 digit numbers.
How many 3 digit numbers can be formed using the digits 2 3 5 6 7 9 if repetition of digits is not allowed?
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
How many 5 digits numbers can be formed using digits?
99999
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many numbers of at least tree different digits can be formed from the integers 123456?
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
How many four digit numbers having all digits distinct can be formed which are not less than 4300?
ans is 2856. But i dont know how to solve... Plz tell....
How many 3 digit numbers can be formed from the digits 24578 if no digits can be repeated?
There are 5*4*3 = 60 such numbers.
How many different positive four digit integers can be formed if the first digit must be even the last digit must be odd and all digits must be distinct?
There are 320 such numbers.
How many digits numbers each less than 500 can be formed from the digits 13467 if repetitions is allowed?
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
How many 4 digit numbers can be formed from the digits 7341 if none of the digits can be repeated?
24
How many 5 digit numbers can be formed from the digits 012 if any of the digits can be repeated?
500
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 4 digit numbers can be formed from the digits 1234567 with no duplicate numbers?
840
