Transpose matrix in data structure

Answer 1

DataStructure-Program to transpose a sparse matrix.#include

#include

#include

#define MAX1 3

#define MAX2 3

struct sparse

{

int *sp ;

int row ;

} ;

void initsparse ( struct sparse * ) ;

void create_array ( struct sparse * ) ;

void display ( struct sparse ) ;

int count ( struct sparse ) ;

void create_tuple ( struct sparse *, struct sparse ) ;

void display_tuple ( struct sparse ) ;

void transpose ( struct sparse *, struct sparse ) ;

void display_transpose ( struct sparse ) ;

void delsparse ( struct sparse * ) ;

void main( )

{

struct sparse s[3] ;

int c, i ;

for ( i = 0 ; i <= 2 ; i++ )

initsparse ( &s[i] ) ;

clrscr( ) ;

create_array ( &s[0] ) ;

printf ( "\nElements in Sparse Matrix: " ) ;

display ( s[0] ) ;

c = count ( s[0] ) ;

printf ( "\n\nNumber of non-zero elements: %d", c ) ;

create_tuple ( &s[1], s[0] ) ;

printf ( "\n\nArray of non-zero elements: " ) ;

display_tuple ( s[1] ) ;

transpose ( &s[2], s[1] ) ;

printf ( "\n\nTranspose of array: " ) ;

display_transpose ( s[2] ) ;

for ( i = 0 ; i <= 2 ; i++ )

delsparse ( &s[i] ) ;

getch( ) ;

}

/* initialises data members */

void initsparse ( struct sparse *p )

{

p -> sp = NULL ;

}

/* dynamically creates the matrix of size MAX1 x MAX2 */

void create_array ( struct sparse *p )

{

int n, i ;

p -> sp = ( int * ) malloc ( MAX1 * MAX2 * sizeof ( int ) ) ;

for ( i = 0 ; i < MAX1 * MAX2 ; i++ )

{

printf ( "Enter element no. %d:", i ) ;

scanf ( "%d", &n ) ;

* ( p -> sp + i ) = n ;

}

}

/* displays the contents of the matrix */

void display ( struct sparse s )

{

int i ;

/* traverses the entire matrix */

for ( i = 0 ; i < MAX1 * MAX2 ; i++ )

{

/* positions the cursor to the new line for every new row */

if ( i % MAX2 0 )

printf ( "\n" ) ;

printf ( "%d\t", * ( p.sp + i ) ) ;

}

}

/* deallocates memory */

void delsparse ( struct sparse *p )

{

free ( p -> sp ) ;

}