Best Answer

Let the nu bers be n,n+1, n+2, & n+3

Hence

n + n+1 + n+2 + n+3 = 75

4n + 6 = 75

4n = 69

n = 69/4

n = 17 remainder '1'

So there are no four whole number that sum to 75.

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There is no set of four consecutive whole numbers whose sum is 75.

Q: What 4 consecutive whole numbers have a total of 75?

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Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.

37 and 38

I can find 5: 37 (in a sequence of 2) ie 37 + 38 24 (3) 13 (5) 10 (6) 3(10)

The numbers, when summed, are 75, 77, 79 and 81.

13 if you include the '75', 12 if you don't.

Related questions

There is no set of 8 consecutive whole numbers whose sum is 75.

Divide the sum of the three consecutive numbers by 3: 75/3=25. The smallest of these numbers will be one less than 25 and the largest will be one more than 25, so the three consecutive numbers will be 24, 25, and 26.

13 + 14 + 15 + 16 + 17 = 75

75 is a whole number. Two consecutive whole numbers can't lie between a single whole number. It's possible you want to know about the square root of 75 which lies between 8 and 9, but we can't know that for sure.

24 + 25 + 26 = 75

75 and 76

74 + 75

5625

The numbers are 37 and 38.

The numbers are 73, 74, 75, 76 and 77.

Whole no are the number which begin from 0 Factors of 75 are 5x5x3 All the numbers are whole numbers.

The numbers are 11, 13, 15, 17 and 19.