y=x y=6-x Set the two equations equal to each other to yield a solution: x=6-x 2x=6 x=3 x=3 will satisfy both equations, that is plugging in x=3 will give the same value for y y=(3)=3 y=6-(3)=3
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
3y+18=7y-6
One way is to look at the graphs of these equations. If they intersect, the point of intersection (x, y) is the only solution of the system. In this case we say that the system is consistent. If their graphs do not intersect, then the system has no solution. In this case we say that the system is inconsistent. If the graph of the equations is the same line, the system has infinitely simultaneous solutions. We can use several methods in order to solve the system algebraically. In the case where the equations of the system are dependent (the coefficients of the same variable are multiple of each other), the system has infinite number of solutions solution. For example, 2x + 3y = 6 4y + 6y = 12 These equations are dependent. Since they represent the same line, all points that satisfy either of the equations are solutions of the system. Try to solve this system of equations, 2x + 3y = 6 4x + 6y = 7 If you use addition or subtraction method, and you obtain a peculiar result such that 0 = 5, actually you have shown that the system has no solution (there is no point that satisfying both equations). When you use the substitution method and you obtain a result such that 5 = 5, this result indicates no solution for the system.
x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.
(3, 6)-------------------Let's see.(6) = 3(3) - 33(3) - (6) = 36 = 9 - 39 - 6 = 36 = 63 = 3========== (3, 6) is a solution to the system of equations. The only solution? I do not know.
Two equations that have the solution of (3, 6) could be: 2x + y = 12 When x = 3 and y = 6, the equation becomes 2(3) + 6 = 12, which is true. x + 2y = 15 Substituting x = 3 and y = 6 into the equation gives 3 + 2(6) = 15, which is also true.
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y=x y=6-x Set the two equations equal to each other to yield a solution: x=6-x 2x=6 x=3 x=3 will satisfy both equations, that is plugging in x=3 will give the same value for y y=(3)=3 y=6-(3)=3
What is the solution set for the equations x-y=2 and -x+y=2
Um there are an infinite number of equations but some simple ones are: X + 1 = 6 X + 2 = 7 123553X = 617765
4+4=8 2+6=8
Symbols not visible. Please resubmit using words eg "plus", "equals" etc
These equations are when the numbers are combined and sometimes divided. There are many more than simply 8 of these equations.
A system of equations? 2X - Y = 3 X + Y = 6 I will try substitution. Express one variable in terms of the other ( use X + Y = 6 ) X + Y = 6 Y = - X + 6 insert into other equation 2X - ( - X + 6) = 3 2X + X - 6 = 3 3X = 9 X = 3 ------- put that back into one of the equations (3) + Y = 6 Y = 3 ------- check both equations 2(3) - (3) = 3 6 - 3 = 3 3 = 3 first equation checks (3) + (3) = 6 6 = 6 Both equations check X = 3 Y = 3 are both true solutions for this system of equations
9 = 6 + s - 3 Collect 'like terms' on the RHS (Right hand Side) 7 Hence 9 = 3 + s Subtract '3' from both sides 6 = s or s = 6 The Answer!!!!
When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.