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Q: Is 3 6 a solution to this system of equations y 3x - 3 3x - y 3?
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Solve by substitution y equals -4x - 7 and y equals 3x?

The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).


Find the solution to the system of equations 3x plus y plus z equals 6 3x - y plus 2z equals 9 y plus z equals 3?

3x + y + z = 63x - y + 2z = 9y + z = 3y + z = 3y = 3 - z (substitute 3 - z for y into the first equation of the system)3x + y + z = 63x + (3 - z) + z = 63x + 3 = 63x = 3x = 1 (substitute 3 - z for y and 1 for x into the second equation of the system)3x - y + 2z = 93(1) - (3 - z) + 2z = 93 - 3 + z + 2z = 93z = 9z = 3 (which yields y = 0)y = 3 - z = 3 - 3 = 0So that solution of the system of the equations is x = 1, y = 0, and z = 3.


What is the solution of this system 3x plus 4y equals 5 x-4y equals 7?

Add the two equations and get 4x = 12 so x = 3 and y = -1


Is the system of equations 3x-6y equals 12 and 2x-4y equals 3 dependent consistent inconsistent or independent?

The system is inconsistent because there is no solution, i.e., no ordered pair, that satisfies both equations. You can see that this will be the case by seeing that their graphs have the same slope (2) but different y-intercepts (2 and 3/4 respectively). So the lines are parallel and will not intersect.


What is the solution of the following system of equations 3y - 2x equals 3 y equals x?

x = y = 3

Related questions

What is the solution to this system of equations y equals -3x-2?

-1


Is 3 6 a solution to this system of equations yequals3x - 3 3x - yequals3?

(3, 6)-------------------Let's see.(6) = 3(3) - 33(3) - (6) = 36 = 9 - 39 - 6 = 36 = 63 = 3========== (3, 6) is a solution to the system of equations. The only solution? I do not know.


Is (63) a solution to this system of equations y3x-3 3x-y3?

Without any equality signs the given expressions can't be considered to be equations.


What is the value of the y variable in the solution to the following system of equations- 3x - 6y equals 3 7x - 5y equals -11?

If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2


The system of equations 3x-6y equals 20 and 2x-4y equals 3 is?

the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.


Solve the system using elimination 3x -9y equals 3?

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.


Is (3 -2) a solution to this system of equations y -3x plus 7 4x and ndash y 10?

Without any equality signs the given terms can't be considered to be equations.


Is (-1 1) a solution to this system of equations y 3x 4 4y - 3 x -7?

Without any equality signs the given terms can't be considered to be equations


Can you solve the system using elimination 3x plus 9y equals 3?

No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.


Is (2, 3) a solution to this system of equations?

No


Solve by substitution y equals -4x - 7 and y equals 3x?

The easiest way to solve this system of equations is to solve for a variable in one of the equations. In the second equation, y = 3x. This can be substituted into the first equation: y = -4x - 7; 3x = = -4x - 7; 7x = -7; x = -1. Since we have determined that x equals -1, we can then substitute -1 into either equation to find our corresponding y-value. Thus: y = 3x; y = 3(-1) y = -3. Thus, the solution to this system of equations is (-1, -3).


Find the solution to the system of equations 3x plus y plus z equals 6 3x - y plus 2z equals 9 y plus z equals 3?

3x + y + z = 63x - y + 2z = 9y + z = 3y + z = 3y = 3 - z (substitute 3 - z for y into the first equation of the system)3x + y + z = 63x + (3 - z) + z = 63x + 3 = 63x = 3x = 1 (substitute 3 - z for y and 1 for x into the second equation of the system)3x - y + 2z = 93(1) - (3 - z) + 2z = 93 - 3 + z + 2z = 93z = 9z = 3 (which yields y = 0)y = 3 - z = 3 - 3 = 0So that solution of the system of the equations is x = 1, y = 0, and z = 3.