Here are some consecutive odd integers. All must follow this form: x+x+2+x+2=3x + 6
6 is divisible by 3. So is 3x. If you add two integers that are divisible by 3, it is still divisible by three.
The question is not about odd integers, but consecutive integers.
This should be x + x+1 + x+2 =3x+3
A bit simpler would be the three in a row : x-1, x, x+1 which add up to 3x which can be divided by 3.
There is no set of three consecutive integers for 187.
9240 is the product of the three consecutive integers 20, 21, and 22.
Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
6,12,18.
Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.
yes always this is true' example 1,2,3 sum is 6 and is divisible by 3
Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.
Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
There is no set of three consecutive integers for 187.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
There is no set of three consecutive integers for 106.
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
9240 is the product of the three consecutive integers 20, 21, and 22.