4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2
it means that instead of having (2x-3)2 you write 4x2-12x+9
Jjg
No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
Multiply by 4. 4x2 - 12x + 9 factors to (2x - 3)(2x - 3) or (2x - 3)2
4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2
(x - 3)(x - 9)
If you are looking for common factors of 12x and 9 it would be 3.
(2x + 3)(2x + 3)
it means that instead of having (2x-3)2 you write 4x2-12x+9
You need to rivse your question. It appears that there is not an equation here. 4*2+12x+9? You can't really solve this it is more of a statement. You can however simplify it to 12x+17- Whoever wrote this obviously can't read. It's supposed to be 4x^2+12x+9 (2x+3)(2x+3)
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
Jjg
(2x - 3)(2x + 3)(4x2 + 9)