4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3)
= (2x - 3)(2x - 3) or (2x - 3)2
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.
An equation with two equal signs is really to explicit equations (or three implicit ones). For example, expession 1 = expression 2 = expression 3 is equivalent to expression 1 = expression 2 AND expression 2 = expression 3 and, by transitivity, expression 1 = expression 3 So you need to solve two of the above three.
No. You need at least four.
2y2 - 2y - 24 has the factors (2y + 6) and (y - 4) There is a formula, but I always use trial and error. The factors of the non-x element need to be such that they can be added to give the middle element. So when you get 24, then you need to be looking at 2,12 - 3,8 - 4,6 When both the second and third element are minus values then there is a plus and a minus in the factors.
To "evaluate" an expression, you need to know the value for the variables.
you cant really simpliffy that expression you need an equation so just write 'cannot simplify' or 'already in simplest form'
You could not.1 - 2cos2theta is an expression which cannot be solved nor evaluated without information about theta. If you need to show its equivalence to another expression then it is necessary to know what the other expression is.
The question contains an expression, not an equation (nor inequality). An expression cannot be solved. Without the value of x, it cannot be evaluated. And, since the numerator and denominator have no common factor, it cannot be simplified. You need to consider what exactly it is that you want a resubmit a question that makes sense.
x^(2)- x + 2 (x -2)( x + 1) NB This does NOT factor becasue '-2' X (+)1 = -2 ( as the middle term. Since the middle term is '-1x' , then '-1' Not equal to '-2'. However, x^(2) - x -2 does factor to ( x - 2)(x + 1)
To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)
-- The number that (x2-y2) represents depends on the values of 'x' and 'y', which you haven't seen fit to include. -- When (x2-y2) is factored, it can be represented as [ (x+y) times (x-y) ], which is often easier to evaluate, or integrate, or differentiate, than the original expression is. But you still need to know the values of 'x' and 'y'.
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.Second, in order to solve a system with two unknown variables, you need two equations, not just one.
X squared minus 5 is not necessarily prime. For instance; if x=3, then x squared minus 5 is 4, and 4 is not prime. Please consider this addition to the above answer. I opted to keep the original answer there for a reason... Whether x^2-5 is prime depends not on the values of x that you plug into the expression, but rather on the primality of the expression itself. In other words, the expression's primality (primeness) is based on the presence or absence of RATIONAL ROOTS. x^2-5 can be factored into (x+√5)(x-√5), making x=±√5. √5 is IRRATIONAL, and since no root of the original expression is rational, the original expression is PRIME. It is ALWAYS PRIME. For the sake of improved clarity, consider the following examples: x^2-4 is NOT PRIME because it can be represented by (x+2)(x-2), making x=±2, both of which are RATIONAL ROOTS. x^2-3 is PRIME because it can be represented by (x+√3)(x-√3), making x=±3, both of which are IRRATIONAL. I hope this helps! Please ask for clarification if you need it, as well as for any other form of assistance... including other questions.
( x - y )2There isn't enough information to answer this question because they have two squared variables and you do not know what is being squared. You would first need to either know the value of one of the variables and an equation of the value of both of the variables before you would be able to factor.
n2 - 11n - 26what two factors of - 26 add up to - 11?(n + 2)(n - 13)===========
There's nothing to solve. If it equaled something, you could solve it. For example, if x^2 - 28 = 0, then x = the square root of 28, which simplifies to plus or minus 2 times the square root of 7.
The minus (unary) operator is of lower precedence than the exponent. To force the square of a negative on some calculators you may need to surround the number in parentheses. E.g.