4x2 - 12x + 9 = 5; whence,
2x - 3 = ±√5, and
2x = 3 ±√5.
Therefore,
x = ½ (3 ±√5).
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1 If: y = 4x2-12x-3 and y = x2+11x+5 2 Then: 4x2-12x-3 = x2+11x+5 3 And so: 3x2-23x-8 = 0 4 Using the quadratic equation formula: x = -1/3 or x = 8 5 By substitution they intersect at: (-1/3, 13/9) and (8, 157) 6 Length: square root of (-1/3-8)2+(13/9-157)2 = 155.7786099 7 Distance between intersections: 155.779 rounded to 3 decimal places
12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12
3x-8+5x+39+4x+51 = x(3+5+4) + -8 + 39 + 51 = 12x +82
(2x - 5)(2x - 5) or (2x - 5) squared