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We will have to use completing the square here.

y = x^2 + 2x - 1

set to 0

x^2 + 2x - 1 = 0

x^2x + 2x = 1

now, halve the coefficient of the linear term ( 2x ), square it and add it to both sides

x^2 + 2x + 1 = 1 + 1

factor the left side; add up right side

(x + 1)^2 = 2

subtract 2 from both sides

(x + 1)^2 - 2 = 0

(-1,-2) is the vertex

my TI-84 confirms this from original equation

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