Question can be taken as multiple meanings. Please see discussion.
it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
No, it is not.No, it is not.
Line of symmetry: x = 3
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
{-1,7}
It is the equation of a parabola.
X equals 0.5at squared is a quadratic equation. It describes a parabola. Y equals mx plus b is a linear equation. It describes a line. You cannot describe a parabola with a linear equation.
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
The equation does not represent that of a parabola.
Left
Yes.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
no
Y = X2 forms a parabola
A U shaped parabola
It is the parabola such that the coordinates of each point on it satisfies the given equation.
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.