It is x - y + 2 = 0
X squared is not an inverse function; it is a quadratic function.
∫ f'(x)/[f(x)√(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.
squared 3
5
The square of r increased by a quantity that is fifty times the cube of k can be written as r squared + 50 (k cubed). It cannot be solved any further.
8
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
X squared is not an inverse function; it is a quadratic function.
Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.
The Distance Formula! D = square root of (y2-y1) quantity squared + (x2-x1) quantity squared
This expression factors as x -1 quantity squared.
∫ f'(x)/[f(x)√(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.
squared 3
∫ f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
a quantity multiplied by itself
one quantity varies directly as the square of the other quantity. in symbols, y = kx squared
They are at x = -3 and x = -2.