q3 - q2 + 2q - 2 = (q2+ 2)(q - 1).
*
If you are prepared to enter the realm of complex numbers
(where i = √(-1) ), then
(i√2)2 = 2(i2) = -2, and
q2 + 2 = q2 - (i√2)2
= (q - i√2)(q + i√2);
and, in this case, the complete factorization is
q3 - q2 + 2q - 2 = (q2 + 2)(q - 1)
= (q - i√2)(q + i√2) (q - 1).
n(2n - 1)(2n + 7)
Factor out the GCF and get X(X2-X+1).
This expression factors as x -1 quantity squared.
That factors to (x - 5)(x - 1)
y^3 + y^2 - 6 (y+2) (y-3) i think
You have to put your heart into it!
(a - 2)(a^2 + 6)
2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222
(x - 2)(x^2 + x + 3)
(x - 5)(x^2 + 1)
(x + 2)(3x - 1)(3x + 1)
9y cubed plus 2y squared
x(x - 19)(x - 1)
105 squared plus 8 cubed is equal to 11,537.
-2, 1.74 and 0.46
n(2n - 1)(2n + 7)
Factor out the GCF and get X(X2-X+1).